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12x^2-90x+150=0
a = 12; b = -90; c = +150;
Δ = b2-4ac
Δ = -902-4·12·150
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-30}{2*12}=\frac{60}{24} =2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+30}{2*12}=\frac{120}{24} =5 $
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